Q&A for How to Decompose Numbers

63 = 60 + 3. 28 = 20 + 8. 63 - 28 = (60 + 3) - (20 + 8) = 60 + 3 - 20 - 8 = 35.

1,000,000 + 0 + 0 + 0 + 0 + 0 + 0.

29 - 13 = (20 + 9) - (10 + 3) = (20 - 10) + ( 9 - 3) = (10) + (6) = 16.

In a practical sense, it's already decomposed, but technically you could express it as 100 + 0 + 0.

1 3/8 = 1.375 = 1 + .3 + .07 + .005.

758 can be decomposed into (7x100) + (5x10) + (8x1) or 700 + 50 + 8. 924 can be decomposed as (9x100) + (2x10) + (4x1) or 900 + 20 + 4.

You can decompose 395 as 300 + 90 + 5 or as (3 x 100) + (9 x 10) + (5 x 1).

In unit form, decompose that number into (3x10)+(1x1)+(5x.1)+(7x.01).

18.3 can be decomposed into either 10+8+.3 or (1x10)+(8x1)+(3x.1). 14 can be decomposed into either 10+4 or (1x10)+(4x1).

The decomposition is either (3x10)+(4x1)+(4x.1)+(6x.01)+(1x.001) or 30+4+.4+.06+.001.

In the first way, show each number breaking down into its component parts as it moves across the row of numbers with plus signs (i.e.: 666=600+60+6). In the second way, show each decomposition through its component parts using the sums of component products of each unit type. (i.e.: 666=(6x100)+(6x10)+(6x1)).

Besides breaking it down into 1 ten and 2 ones, there's also 10+2!

9 is 1 away from 10, so taking 1 from 7 will leave you with the addends 1 and 6. Hence, A. 1+6 is your correctly decomposed answer.

132 = 100 + 30 + 2, with 30 and 2 being in the tens and ones places. You can also decompose it further as (1x100) + (3x10) + (2x1).

You can decompose it into (20 x $1), (4 x $5), (2 x $10), or (1 x $20).

You can decompose 567 as 500+60+7 or (5x100)+(6x10)+(7x1).

You can decompose 6057 as either 6000 + 50 + 7 or (6 × 1000) + (5 × 10) + (7 × 1).

Decompose that into either (2x100) + (3x10) + (7x1) or 200 + 30 + 7.

Ten sticks can be broken down into ten single sticks, parts of 5 (5 and 5), or unequal parts adding up to 10 (9 and 1, 8 and 2, 7 and 3, or 6 and 4).

You can decompose the numbers into their place values and then subtract their parts: 13 is 10 + 3 and 6 is 6 + 0, so (10 - 6) + (3 - 0) = 4 + 3 = 7. Alternatively, break it into smaller steps by separating 13 into 10 and 3, then subtract 3 from 13, and 3 again from the remaining three, to get 7.

To decompose a decimal, break it apart through expanded form or express it as an addition problem. For example, you can decompose 6.678 into 6 + 0.6 + 0.07 + 0.008 or (6 x 1) + (6 x 0.1) + (7 x 0.01) + (8 x 0.001).

To decompose 945, break it into its components: 945 = 900 + 40 + 5, or as (9 x 100) + (4 x 10) + (5 x 1).

Use the properties of addition to break apart one of the factors and add them together: 8x7=(8x5)+(8x2)=40+16=56. Alternatively, you can break them into smaller parts: 8x7=(8x4)+(8x3)=32+24=56. You can also use the distributive property: 8x7=8x(5+2)=(8x5)+(8x2)=40+16=56.

Since 50+50=100 and are both equal addends, to decompose 100, you add 50 and 50 (100=50+50).

Break 62 into parts and divide each by 4. For example, 62 can be decomposed into 60 and 2. Dividing each by 4 gives you 60/4 = 15 and 2/4 = 0.5. Adding those gives you 15.5.

To decompose these numbers, separate them into tens and ones. 22 becomes 20 + 2, and 48 becomes 40 + 8. Add each corresponding part: (20 + 40) + (2 + 8) = 60 + 10 = 70. Your answer is 70.

To decompose this using place value, multiply each digit of 486 by 5 (400 × 5, 80 × 5, 6 × 5) to get 2000, 400, and 30, then add those results together. The answer is 2430.

To decompose 548 × 8, break down 548 into parts: 500 × 8 = 4000, 40 × 8 = 320, and 8 × 8 = 64. Then, add these results together to get 4384.

To decompose these numbers, break each one into its components: 2583 becomes 2000 + 500 + 80 + 3, and 673 becomes 600 + 70 + 3. Then, add the corresponding parts: 2000 + 600 = 2600, 500 + 70 = 570, 80 + 3 = 83, which totals 3253.

400 is already a decomposed number, but you can write it as 40 x 10.